12x^2-120x+240=0

Solution for 12x^2-120x+240=0 equation:

12x^2-120x+240=0

a = 12; b = -120; c = +240;
Δ = b2-4ac
Δ = -1202-4·12·240
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-24\sqrt{5}}{2*12}=\frac{120-24\sqrt{5}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+24\sqrt{5}}{2*12}=\frac{120+24\sqrt{5}}{24}
$